比赛 |
20251022赛前模拟1 |
评测结果 |
AAAAAAAAAAAAAAAAAAAA |
题目名称 |
正负游戏 |
最终得分 |
100 |
用户昵称 |
梦那边的美好ME |
运行时间 |
0.105 s |
代码语言 |
C++ |
内存使用 |
5.50 MiB |
提交时间 |
2025-10-22 10:41:21 |
显示代码纯文本
#include<bits/stdc++.h>
using namespace std;
#define ll long long
const ll mod=998244353;
ll n,m,k;
vector<ll>rowc,rown,colc,coln;
ll mpow(ll a,ll b){
ll res=1;
while(b>0){
if(b&1)res=res*a%mod;
a=a*a%mod;
b>>=1;
}
return res;
}
int main(){
freopen("plusminus.in","r",stdin);
freopen("plusminus.out","w",stdout);
// freopen("in.in","r",stdin);
scanf("%lld %lld %lld",&n,&m,&k);
if((n%2)!=(m%2)){
printf("0\n");
return 0;
}
rowc.resize(n+1,0);
rown.resize(n+1,0);
colc.resize(m+1,0);
coln.resize(m+1,0);
bool possible=1;
for(int i=1;i<=k;i++){
ll x,y,z;
scanf("%lld %lld %lld",&x,&y,&z);
rowc[x]++;
colc[y]++;
if(z==-1){
rown[x]++;
coln[y]++;
}
if(rowc[x]>m||(rowc[x]==m&&rown[x]%2==0)){
possible=0;
}
if(colc[y]>n||(colc[y]==n&&coln[y]%2==0)){
possible=0;
}
}
if(!possible){
printf("0\n");
return 0;
}
ll num=(n-1)*(m-1)-k;
printf("%lld\n",mpow(2,num));
return 0;
}