比赛 |
20101110 |
评测结果 |
AAAAAAAAAAAAATTTTTAT |
题目名称 |
移动服务 |
最终得分 |
70 |
用户昵称 |
belong.zmx |
运行时间 |
0.000 s |
代码语言 |
Pascal |
内存使用 |
0.00 MiB |
提交时间 |
2010-11-10 21:38:04 |
显示代码纯文本
program service(input,output);
var
c:array[1..200,1..200]of longint;
n,m:longint;
p:array[0..1000]of longint;
f:array[0..1,1..200,1..200]of longint;
i,j,k,ans:longint;
function min(a,b:longint):longint;
begin
if a>b then min:=b else min:=a;
end;
begin
assign(input,'service.in');
reset(input);
readln(m,n);
for i:=1 to m do
begin
for j:=1 to m do read(c[i,j]);
readln;
end;
for i:=1 to n do read(p[i]);
close(input);
for i:=0 to 1 do
for j:=1 to m do
for k:=1 to m do f[i,j,k]:=maxlongint;
f[0,1,2]:=0;
f[0,2,1]:=0;
p[0]:=3;
for i:=0 to n-1 do
begin
for j:=1 to m do
for k:=1 to m do f[(i+1)mod 2,j,k]:=maxlongint;
for j:=1 to m do
for k:=1 to m do
begin
if (f[i mod 2,j,k]<maxlongint)and(j<>k) then
begin
if (k<>p[i+1])and(p[i]<>p[i+1]) then
begin
f[(i+1) mod 2,k,p[i]]:=min(f[(i+1) mod 2,k,p[i+1]],f[i mod 2,j,k]+c[j,p[i+1]]);
f[(i+1) mod 2,p[i],k]:=min(f[(i+1) mod 2,p[i],k],f[(i+1) mod 2,k,p[i]]);
end;
if (j<>p[i+1])and(p[i]<>p[i+1]) then
begin
f[(i+1) mod 2,j,p[i]]:=min(f[(i+1) mod 2,j,p[i+1]],f[i mod 2,j,k]+c[k,p[i+1]]);
f[(i+1) mod 2,p[i],j]:=min(f[(i+1) mod 2,p[i],j],f[(i+1) mod 2,j,p[i]]);
end;
if (j<>p[i+1])and(k<>p[i+1]) then
begin
f[(i+1) mod 2,j,k]:=min(f[(i+1) mod 2,j,k],f[i mod 2,j,k]+c[p[i],p[i+1]]);
f[(i+1) mod 2,k,j]:=min(f[(i+1) mod 2,k,j],f[(i+1) mod 2,j,k]);
end;
end;
end;
end;
assign(output,'service.out');
rewrite(output);
ans:=maxlongint;
for i:=1 to m do
for j:=1 to m do
ans:=min(ans,f[n mod 2,i,j]);
writeln(ans);
close(output);
end.