比赛 |
ZLXSCDay1 |
评测结果 |
AAAAAAAAAA |
题目名称 |
PERICA |
最终得分 |
100 |
用户昵称 |
铁策 |
运行时间 |
0.372 s |
代码语言 |
C++ |
内存使用 |
0.70 MiB |
提交时间 |
2016-03-18 18:50:54 |
显示代码纯文本
#include <iostream>
#include <cstdio>
#include <algorithm>
#define MOD 1000000007
using namespace std;
int n, k;
int x[100010];
int gcd(long long x, long long y)
{
return (y ? gcd(y, x % y) : x);
}
void ex_gcd(long long a, long long b, long long &x, long long &y)
{
if (!b)
{
x = 1;
y = 0;
return;
}
long long x1, y1;
ex_gcd(b, a % b, x1, y1);
x = y1,y = x1 - (a / b) * y1;
}
inline long long getrev(long long a, long long mod)
{
if (!a || gcd(a, mod) > 1)
return -1;
long long x, y;
ex_gcd(a, mod, x, y);
return (x + mod) % mod;
}
int main()
{
freopen("perica.in", "r", stdin);
freopen("perica.out", "w", stdout);
scanf("%d%d", &n, &k);
for (int i = 0; i < n; i++)
scanf("%d", &x[i]);
sort(x, x + n);
long long now = 1, ans = x[k - 1];
for (int i = k; i < n; i++)
{
long long t = getrev(i - k + 1, MOD);
now = (now * t) % MOD;
now = (now * i) % MOD;
ans = (ans + x[i] * now) % MOD;
}
printf("%lld\n", ans);
return 0;
}