记录编号 |
559027 |
评测结果 |
AAAAAAAAAA |
题目名称 |
最大子序和 |
最终得分 |
100 |
用户昵称 |
yrtiop |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.072 s |
提交时间 |
2021-02-09 17:36:32 |
内存使用 |
3.08 MiB |
显示代码纯文本
- #include <cstdio>
- #include <cstring>
- #include <algorithm>
- using namespace std;
- const int maxn = 300005;
- int q[maxn],head = 1,tail = 0,n,m;
- long long a[maxn],sum[maxn];
- int main() {
- freopen("maxsubseqsum.in","r",stdin);
- freopen("maxsubseqsum.out","w",stdout);
- scanf("%d%d",&n,&m);
- for(int i = 1;i <= n;++ i) {
- scanf("%lld",&a[i]);
- sum[i] = sum[i - 1] + a[i];
- }
- long long ans = a[1];
- q[++ tail] = 0;
- for(int i = 2;i <= n;++ i) {
- while(head <= tail&&i - q[head] > m)++ head;
- ans = max(ans , sum[i] - sum[q[head]]);
- while(head <= tail&&sum[q[tail]] > sum[i - 1])-- tail;
- q[++ tail] = i - 1;
- }
- printf("%lld",ans);
- fclose(stdin);
- fclose(stdout);
- return 0;
- }