| 记录编号 |
608915 |
评测结果 |
AAAAAAAAA |
| 题目名称 |
4188.Symmetric Mountains |
最终得分 |
100 |
| 用户昵称 |
李金泽 |
是否通过 |
通过 |
| 代码语言 |
C++ |
运行时间 |
0.742 s |
| 提交时间 |
2025-10-30 15:58:10 |
内存使用 |
52.45 MiB |
显示代码纯文本
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<algorithm>
#define N 5005
#define ll long long
#define ul unsigned long long
#define int long long
#define db double
#define fo(i,l,r) for(int i=l;i<=r;i++)
#define rf(i,r,l) for(int i=r;i>=l;i--)
int n,m,a[N],f[N][N],ans;const int inf=1e18;
int abs(int x,int y){return x>y?x-y:y-x;}
void swap(int &x,int &y){int t=x;x=y;y=t;}
int max(int x,int y){return x>y?x:y;}
int min(int x,int y){return x<y?x:y;}
int read(){
int sum=0;bool f=0;char c=getchar();
for(;c<48||c>57;c=getchar())if(c==45)f=1;
for(;c>=48&&c<=57;c=getchar())sum=sum*10+(c&15);
return f?-sum:sum;
}
signed main(){
freopen("Mountains.in","r",stdin);freopen("Mountains.out","w",stdout);
n=read();fo(i,1,n)a[i]=read();
printf("0 ");
fo(k,2,n)
{
ans=inf;
for(int i=1,j=i+k-1;j<=n;i++,j++)
ans=min(ans,f[i][j]=f[i+1][j-1]+abs(a[i],a[j]));
printf("%lld ",ans);
}
return 0;
}