记录编号 |
340093 |
评测结果 |
AAAAAAAAAAAAA |
题目名称 |
[USACO Hol10] 政党 |
最终得分 |
100 |
用户昵称 |
sxysxy |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
2.933 s |
提交时间 |
2016-11-06 10:26:19 |
内存使用 |
8.03 MiB |
显示代码纯文本
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <string>
#include <cstdarg>
#include <algorithm>
#include <vector>
#include <list>
#include <queue>
#include <functional>
using namespace std;
#define MAXN 200001
vector<int> G[MAXN];
int size[MAXN], top[MAXN], parent[MAXN];
int deep[MAXN], son[MAXN];
void dfs(int u, int f, int d)
{
size[u] = 1;
parent[u] = f;
deep[u] = d;
for(int i = 0; i < G[u].size(); i++)
{
int to = G[u][i];
if(to != f)
{
dfs(to, u, d+1);
size[u] += size[to];
if(size[son[u]] < size[to])
son[u] = to;
}
}
}
void dfs(int u, int tp)
{
top[u] = tp;
if(!son[u])return;
dfs(son[u], tp);
for(int i = 0; i < G[u].size(); i++)
{
int to = G[u][i];
if(to != parent[u] && to != son[u])
dfs(to, to);
}
}
int lca(int u, int v)
{
int t1 = top[u], t2 = top[v];
while(t1 != t2)
{
if(deep[t1] < deep[t2])
{
swap(u, v);
swap(t1, t2);
}
u = parent[t1];
t1 = top[u];
}
return deep[u]<deep[v]?u:v;
}
inline int dist(int u, int v)
{
return deep[u]+deep[v]-(deep[lca(u, v)]<<1);
}
vector<int> Z[MAXN];
int main()
{
char *__p__ = (char *)malloc(64<<20)+(64<<20);
__asm__("movl %0, %%esp\n" :: "r"(__p__));
freopen("cowpol.in", "r", stdin);
freopen("cowpol.out", "w", stdout);
int n, k;
scanf("%d %d", &n, &k);
int rt;
for(int i = 1; i <= n; i++)
{
int a, b;
scanf("%d %d", &a, &b);
if(b)
{
G[i].push_back(b);
G[b].push_back(i);
}else rt = i;
Z[a].push_back(i);
}
dfs(rt, 0, 0);
dfs(rt, rt);
for(int i = 1; i <= k; i++)
{
int u = 0;
int ans = 0;
for(int j = 0; j < Z[i].size(); j++)
if(deep[Z[i][j]] > deep[u])
u = Z[i][j];
for(int j = 0; j < Z[i].size(); j++)
if(Z[i][j] != u)
ans = max(ans, dist(u, Z[i][j]));
printf("%d\n", ans);
}
return 0;
}