记录编号 |
351735 |
评测结果 |
AAAAAAAAAAAAAAAAAAAA |
题目名称 |
[NOIP 2014PJ]子矩阵 |
最终得分 |
100 |
用户昵称 |
CodeLyoko |
是否通过 |
通过 |
代码语言 |
Pascal |
运行时间 |
1.749 s |
提交时间 |
2016-11-16 18:47:54 |
内存使用 |
0.15 MiB |
显示代码纯文本
var
i,j,ans,n,m,r,c:longint;
a:array[0..20,0..20]of longint;
rb:array[0..20]of longint;
function min(x,y:longint):longint;
begin
if x>=y then exit(y)
else exit(x)
end;
procedure dp;//动规列
var
t,i,k:longint;
f,hc:array[0..20,0..20]of longint;
zc:array[0..20]of longint;
begin
//dp initialization
fillchar(hc,sizeof(hc),0);
fillchar(zc,sizeof(zc),0);
rb[r+1]:=rb[r];
for i:=1 to m do
for j:=1 to r do
zc[i]:=zc[i]+abs(a[rb[j],i]-a[rb[j+1],i]);
for i:=1 to m-1 do
for j:=i+1 to m do
for k:=1 to r do
hc[i,j]:=hc[i,j]+abs(a[rb[k],i]-a[rb[k],j]);
//dp main
for i:=1 to m do
f[i,1]:=zc[i];
for j:=2 to c do
for i:=j to m do begin//枚举状态
t:=maxlongint;
for k:=j-1 to i-1 do//计算状态(以一个O(m)循环为代价)
t:=min(t,f[k,j-1]+hc[k,i]);
f[i,j]:=t+zc[i];
end;
for i:=c to m do
ans:=min(ans,f[i,c]);
end;
procedure dfs(k,p:longint);//穷搜行
var
i:longint;
begin
if k=r then dp;
for i:=p+1 to n do begin
rb[k+1]:=i;
dfs(k+1,i);
end;
end;
begin
assign(input,'submatrix.in');
reset(input);
assign(output,'submatrix.out');
rewrite(output);
readln(n,m,r,c);
for i:=1 to n do begin
for j:=1 to m do
read(a[i,j]);
readln;
end;
ans:=maxlongint;
dfs(0,0);
writeln(ans);
close(input);
close(output);
end.