| 记录编号 |
577193 |
评测结果 |
AAAATTTTTT |
| 题目名称 |
3738.逆元数列 |
最终得分 |
40 |
| 用户昵称 |
lihaoze |
是否通过 |
未通过 |
| 代码语言 |
C++ |
运行时间 |
6.149 s |
| 提交时间 |
2022-10-25 13:10:51 |
内存使用 |
10.08 MiB |
显示代码纯文本
#include "bits/stdc++.h"
using i64 = long long;
struct Seg {
int l, r;
i64 sum;
};
const int N = 1e5 + 10;
int n, m;
i64 a[N];
Seg tree[4 * N];
#define l(x) tree[x].l
#define r(x) tree[x].r
#define sum(x) tree[x].sum
i64 P;
i64 power(i64 a, i64 b, i64 p) {
i64 ret = 1;
for (; b; b /= 2, a = a * a % p) {
if (b % 2) ret = ret * a % p;
}
return ret % p;
}
i64 inv(i64 a, i64 p) {
return power(a, p - 2, p);
}
void build(int p, int l, int r) {
l(p) = l, r(p) = r;
if (l == r) {
return sum(p) = a[l], void();
}
int mid = l + r >> 1;
build(p * 2, l, mid),
build(p * 2 + 1, mid + 1, r);
sum(p) = sum(p * 2) + sum(p * 2 + 1);
}
void change(int p, int l, int r) {
if (l(p) == r(p) && l <= l(p) && r >= r(p)) {
sum(p) = inv(sum(p), P);
return;
}
int mid = l(p) + r(p) >> 1;
if (l <= mid) change(p * 2, l, r);
if (r > mid) change(p * 2 + 1, l, r);
sum(p) = sum(p * 2) + sum(p * 2 + 1);
}
i64 ask(int p, int l, int r) {
if (l <= l(p) && r >= r(p)) {
return sum(p);
}
int mid = l(p) + r(p) >> 1;
i64 res = 0;
if (l <= mid) res += ask(p * 2, l, r);
if (r > mid) res += ask(p * 2 + 1, l, r);
return res;
}
int main() {
freopen("invarray.in", "r", stdin);
freopen("invarray.out", "w", stdout);
std::cin >> n >> m >> P;
for (int i = 1; i <= n; ++ i) {
std::cin >> a[i];
}
build(1, 1, n);
for (int i = 1; i <= m; ++ i) {
int op, l, r;
std::cin >> op >> l >> r;
if (op == 1) {
change(1, l, r);
} else {
std::cout << ask(1, l, r) << '\n';
}
}
return 0;
}