记录编号 |
586302 |
评测结果 |
AATAAAAAAA |
题目名称 |
[网络流24题] 骑士共存 |
最终得分 |
90 |
用户昵称 |
┭┮﹏┭┮ |
是否通过 |
未通过 |
代码语言 |
C++ |
运行时间 |
1.383 s |
提交时间 |
2024-01-12 18:58:41 |
内存使用 |
3.05 MiB |
显示代码纯文本
#include <bits/stdc++.h>
using namespace std;
//二分图做法
const int N = 5e4+10,M = 5e5+10;
int n,m,ans;
inline int read(){
int x=0,sign=0; char s=getchar();
while(!isdigit(s))sign|=s=='-',s=getchar();
while(isdigit(s))x=(x<<1)+(x<<3)+(s-'0'),s=getchar();
return sign?-x:x;
}
struct made{
int ver,nx;
}e[M];
int hd[N],tot;
int match[N],v[N];
int lx[10] = {0,-2,-1,1,2,2,1,-1,-2},ly[10] = {0,1,2,2,1,-1,-2,-2,-1};
bool a[210][210];
void add(int x,int y){
tot++;
e[tot].nx = hd[x],e[tot].ver = y,hd[x] = tot;
}
int id(int x,int y){
return (x-1)*n+y;
}
bool f(int x,int y){
if(!a[x][y] && x > 0 && y > 0 && x <= n && y <= n)return 1;
return 0;
}
void build(int x,int y){
if(a[x][y])return;
for(int i = 1;i <= 8;i++)
if(f(x+lx[i],y+ly[i]))add(id(x,y),id(x+lx[i],y+ly[i]));
}
bool dfs(int x,int u){
for(int i = hd[x];i;i = e[i].nx){
int y = e[i].ver;
if(v[y] == u)continue;
v[y] = u;
if(!match[y] || dfs(match[y],u)){
match[y] = x;
return 1;
}
}
return 0;
}
int main(){
freopen("knight.in","r",stdin);
freopen("knight.out","w",stdout);
n = read(),m = read();
for(int i = 1;i <= m;i++){
int x,y;
x = read(),y = read();
a[x][y] = 1;
}
for(int i = 1;i <= n;i++)
for(int j = (i&1)?2:1;j <= n;j+=2)build(i,j);
for(int i = 1;i <= n;i++)
for(int j = (i&1)?2:1;j <= n;j+=2)
if(!a[i][j])if(dfs(id(i,j),id(i,j)))ans++;
printf("%d\n",n*n-ans-m);
return 0;
}