记录编号 569337 评测结果 AAAAAAAAAA
题目名称 运输问题1 最终得分 100
用户昵称 Gravataryrtiop 是否通过 通过
代码语言 C++ 运行时间 0.000 s
提交时间 2022-03-02 19:47:21 内存使用 0.00 MiB
显示代码纯文本
  1. #include <cstdio>
  2. #include <cstring>
  3. #include <algorithm>
  4. #include <queue>
  5. using namespace std;
  6. const int maxn = 20005;
  7. int ver[maxn << 1],nxt[maxn << 1],cap[maxn << 1],head[maxn];
  8. int cnt = -1;
  9. int cur[maxn],level[maxn];
  10. queue <int> q;
  11. void add(int u,int v,int t) {
  12. nxt[++ cnt] = head[u];
  13. ver[cnt] = v;
  14. cap[cnt] = t;
  15. head[u] = cnt;
  16. return ;
  17. }
  18. int n;
  19. bool bfs(int s,int t) {
  20. memset(level , 0 , sizeof(level));
  21. q.push(s);
  22. level[s] = 1;
  23. while(!q.empty()) {
  24. int u = q.front();
  25. q.pop();
  26. for(int i = head[u];~ i;i = nxt[i]) {
  27. int v = ver[i];
  28. if(!level[v]&&cap[i]) {
  29. level[v] = level[u] + 1;
  30. q.push(v);
  31. }
  32. }
  33. }
  34. return level[t] != 0;
  35. }
  36. int dfs(int x,int t,int maxflow) {
  37. if(x == t||!maxflow)return maxflow;
  38. int flow = 0,f;
  39. for(int& i = cur[x];~ i;i = nxt[i]) {
  40. int v = ver[i];
  41. if(level[v] == level[x] + 1&&(f = dfs(v , t , min(maxflow , cap[i])))) {
  42. if(!f) {
  43. level[v] = 0;
  44. break ;
  45. }
  46. flow += f;
  47. maxflow -= f;
  48. cap[i] -= f;
  49. cap[i ^ 1] += f;
  50. if(!maxflow)break;
  51. }
  52. }
  53. return flow;
  54. }
  55. int Dinic(int s,int t) {
  56. int flow = 0;
  57. while(bfs(s , t)) {
  58. memcpy(cur , head , sizeof(cur));
  59. flow += dfs(s , t , 0x3f3f3f3f);
  60. }
  61. return flow;
  62. }
  63. int main() {
  64. freopen("maxflowa.in","r",stdin);
  65. freopen("maxflowa.out","w",stdout);
  66. scanf("%d",&n);
  67. memset(head , -1 , sizeof(head));
  68. for(int i = 1;i < n;++ i) {
  69. for(int j = 1;j <= n;++ j) {
  70. int x;
  71. scanf("%d",&x);
  72. add(i , j , x);
  73. add(j , i , 0);
  74. }
  75. }
  76. printf("%d\n",Dinic(1 , n));
  77. fclose(stdin);
  78. fclose(stdout);
  79. return 0;
  80. }