记录编号 |
601941 |
评测结果 |
AAAAAATTTTTTTTTTTTTT |
题目名称 |
3947.[国家集训队 2011]等差子序列 |
最终得分 |
30 |
用户昵称 |
OTTF |
是否通过 |
未通过 |
代码语言 |
C++ |
运行时间 |
3.231 s |
提交时间 |
2025-06-29 17:54:18 |
内存使用 |
3.84 MiB |
显示代码纯文本
#include <cstring>
#include <cstdio>
#include <iostream>
using namespace std;
constexpr int N = 21145;
int t;
int n;
bool flag[N];
int main () {
freopen ("sequence.in", "r", stdin);
freopen ("sequence.out", "w", stdout);
scanf ("%d", &t);
for (int index = 1; index <= t; index++) {
scanf ("%d", &n);
memset (flag, 0, sizeof (flag));
int num;
char ch = 'N';
for (int i = 1; i <= n; i++) {
scanf ("%d", &num);
if (ch == 'Y') {
continue;
}
for (int j = 1; j < num; j++) {
if (num + (num - j) <= n && (flag[j] ^ flag[num + (num - j)])) {
ch = 'Y';
}
}
flag[num] = true;
}
printf ("%c\n", ch);
}
return 0;
}