记录编号 |
23270 |
评测结果 |
AAAAAAAAAA |
题目名称 |
[HAOI 2010]最长公共子序列 |
最终得分 |
100 |
用户昵称 |
苏轼 |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
1.863 s |
提交时间 |
2011-03-06 14:03:42 |
内存使用 |
0.32 MiB |
显示代码纯文本
#include <iostream>
#include <fstream>
#include <string>
#include <cstring>
using namespace std;
string s1, s2;
short f[2][5001];
int g[2][5001];
int main ()
{
ifstream fin("lcs.in");
ofstream fout("lcs.out");
fin >> s1 >> s2;
s1.erase(s1.end()-1);
s2.erase(s2.end()-1);
for (int i=0; i<s2.length(); i++)
g[1][i] = 1;
for (int i=0; i<s1.length(); i++)
{
if (s1[i] == s2[0])
{
f[i%2][0] = 1;
g[i%2][0] = 1;
if (f[(i+1)%2][0] == f[i%2][0])
g[i%2][0] += g[(i+1)%2][0];
}
else
f[i%2][0] = f[(i+1)%2][0],
g[i%2][0] = g[(i+1)%2][0];
for (int j=1; j<s2.length(); j++)
{
if (s1[i] == s2[j])
{
g[i%2][j] = g[(i+1)%2][j-1];
f[i%2][j] = f[(i+1)%2][j-1] + 1;
if (f[(i+1)%2][j] == f[i%2][j])
g[i%2][j] += g[(i+1)%2][j];
if (f[i%2][j-1] == f[i%2][j])
g[i%2][j] += g[i%2][j-1];
}
else
{
if (f[(i+1)%2][j] > f[i%2][j-1])
f[i%2][j] = f[(i+1)%2][j],
g[i%2][j] = g[(i+1)%2][j];
else if (f[(i+1)%2][j] == f[i%2][j-1])
{
f[i%2][j] = f[(i+1)%2][j];
g[i%2][j] = g[(i+1)%2][j] + g[i%2][j-1];
if (f[i%2][j] == f[(i+1)%2][j-1])
g[i%2][j] -= g[(i+1)%2][j-1];
}
else
f[i%2][j] = f[i%2][j-1],
g[i%2][j] = g[i%2][j-1];
}
g[i%2][j] %= 100000000;
}
}
fout << f[(s1.length()-1)%2][s2.length()-1] << endl;
fout << g[(s1.length()-1)%2][s2.length()-1] << endl;
return 0;
}